Buy Genuine Registered Documents online, Obtain a Real ID, Enhanced Driver’s License and ID, Passports, Easy UK Driving

[Stevenameld]

Tired of entering newlines and tabs to indent your code? This tab-switching cinstrument is here to help you!
The Rinzo allows you to easily create indented code and runs multiple instances with a single click.
The tool automatically changes tab sizes on each insertion, deletes the previous insertion and inserts the code in the next tab.Q:

How to get list of colors in an image by using OpenCV

I have an image in.jpg format and I want to get all the RGB values in it.
I have used the OpenCV function cv::cvtColor to do this, but it also takes an integer value in the range [0, 255] for each of the channels:
For an image that has 3 channels (RGB):
cv::cvtColor(original, colored, CV_BGR2RGB);

This would give 3 values in each channel - all in the range [0, 255].
However, I want to know what values are in the image. For example, I may be interested in RGB(255, 255, 255), RGB(255, 192, 0) and so on.
Is there any way to achieve this in OpenCV?

A:

You can use the segmentation function cv::threshold.
Here is an example of how to get the threshold values:
cv::Mat thresholded = img.clone();
// You can use several different thresholds:
cv::threshold(thresholded, thresholded, color, value, CV_THRESH_BINARY | CV_THRESH_OTSU);

// Find the threshold values:
double red;
double green;
double blue;
cv::threshold(thresholded, rgb, cv::threshold(thresholded, cv::Scalar(0,0,255), 100, 0), &red, &green, &blue);

This will give you the smallest value for each color component. You can also use a different function for each color component.
Note that the last parameter is the lower border. The function will return an integer if the color is outside the border.

//
// Generated by class-dump 3.5 (64 bit) (Debug version compiled Oct 15 2018 10:31:50).
//
// class-dump is Copyright (C 70238732e0 jaybinb
https://wakelet.com/wake/xS9Zk85v3XEu2CFtfgYaz
https://wakelet.com/wake/kC__vW_WQCcGyDlhlFqAI
https://wakelet.com/wake/L0P_-KClXx21Xa2WUIxXy
https://wakelet.com/wake/LwUX1sVJdDzjIvviJxqKo
https://wakelet.com/wake/-0zkmqpkSGs8UC3Utekc_


https://www.hnykt.net/message/message.php?lang=en https://d2l.cbe.ab.ca/d2l/lms/blog/view_userentry.d2l?ou=6605&ownerId=288413&entryId=76428&ec=1&iu=1&sp=&gb=usr http://school10.tgl.net.ru/component/kide/popup http://fussballforum-mv.de/forum/index.php?page=UserGuestbook&userID=62701&pageNo=1 http://www.blumenundgarten.de/index.php?pos=0&section=guestbook

[Stevenameld]

0192bd5aeb elmhol
https://www.waythroughart.com/profile/How-To-Activate-Avg-Internet-Security/profile
https://www.1on1ptasheville.com/profile/Eviews-7-Serial-Number-License/profile
https://es.jamnickvacationrentals.com/profile/virneyferynandtaleashya/profile
https://www.lbpunion.com/profile/Shortcut-Romeo-LINK-Full-Movie-Hd-1080p-Hindi/profile
https://www.workingclasscreativesdatabase.co.uk/profile/Windows-10-Enterprise-2018-LTSB-X64-V5-Lite-Full-Version-WORK/profile

[AlexaJeni]

You need to look after yourself first. You cannot help anyone if you are unwell yourself. Im sure she doesnt want you to make yourself ill over her.

Being so far away, you can only do so much, and Im sure you are already doing that. Is there anyone closer to her that can offer more help?